Answer:
Step-by-step explanation:
From the picture attached,
To prove the angles of the given triangles equal in measure,
Lines AB and ED are parallel and a transversal CE is intersecting these lines,
Therefore, ∠DEA ≅ ∠BAC [Corresponding angles]
Similarly, lines DA and BC are parallel and EC is a transversal line.
Therefore, ∠DAE ≅ ∠BCA [Corresponding angles]
Since, two angles of the given triangles are equal in measure, by AA property of similarity ΔADE ~ ΔCBA.
And remaining third angle of the triangles will be equal in measure.