Answer:
The oxygen dissociation curve represents the percentage saturation of Hb with oxygen at different partial pressure of oxygen. The different partial pressures gives sigmoid shapes to the curve. When this curves shifts to right, it indicates low affinity or binding of oxygen by the Hb. it also indicates the unloading or releases of Oxygen by Hb molecules at condition of low pressure. e,g in the muscles during strenuous exercise.However, when the curve shifts to the left, this indicate high affinity for oxygen, great binding, at high partial pressure of oxygen.e,g in the lungs to take oxygen and releases CO2.
Therefore in this scenario, the statement -. <u>During strenuous exercise, the oxygen-hemoglobin dissociation curve shifts to the right.</u> is correct. because oxygen is needed by the muscles therefore ,oxygen should be less binded by Hb, decrease affinity and easily unloaded to muscles.
<u>The statement </u>This rightward shift reflects an increase in the affinity of hemoglobin for oxygen and favors loading of O2 into hemoglobin in the lungs is wrong.
As explained above the rightwards shift indicated low affinity of Hb for oxygen(unloading)and favours unloading at the muscles because during strenuous exercise the partial pressure of oxygen is very low(but that of CO2 high) in the muscles which favours low oxygen molecules binding by Hb, and easy release to respiring cells.
Explanation:
A recessive trait inheritance could be more prevalent in a population than the dominant because mutation could occur because the mating does not have a wide variation causing a lethal gene or an autosomal sex link to be easily passed on the offspring
The buttock region is the most common area for pressure ulcers to develop. Pressure ulcers or bedsores are injuries to skin and the underlying tissue resulting from prolonged pressure on the skin, They most often develop on the skin which covers bony areas of the body, such as hips, tailbone and the heals.
Answer:
Explanation:
The homozygous yellow seeds will be represented by AA and homozygous white plant will be bb (Therefore green seeds will be a and purple flowers B). So using a punnet square, the cross would be AAbb x AaBb