Hello there! Thank you for asking your question here at Brainly! I will be assisting you with answering this question today, and will be teaching you how to handle it on your own in the future.
First, let's take a look at our problem.
"Twice a number and 5 more is 100."
Based on this context, we are looking for a specific number to plug in.
To solve for this, I will rewrite the problem. As I do so, I will be writing (in parenthesis) the translation of an equation.
Twice a number (2x) and 5 more (+5) is 100 (=100).
Let's rewrite everything that's in parenthesis.
2x + 5 = 100
This is our equation.
To solve for this, we will need to do some basic algebra. Of course, I will teach you how to handle this on your own in future scenarios.
2x + 5 = 100
To solve for x, we need to isolate 2x, and then divide both sides by 2.
2x + 5 = 100
Subtract 5 from both sides to isolate 2x.
5 - 5 = 0
100 - 5 = 95
We now have the following equation:
2x = 95
Divide both sides by 2 to solve for x.
2x / 2 = x
95 / 2 = 47.5
x = 47.5
47.5 is your number.
I hope this helps!
First of all, what is an integer?
Integers are numbers such as -7, -4, 0, 5, 16... etc...
This means that even integers are numbers such as:
-4, -2, 0, 2, 4, 6, 8, 10... etc...
Which means that:
AUB={..., -4, -2, 0, 2, 4, 5, 6, 7, 8, 10, 12, 14, ...}
This is because:
The union "<span>U</span>" of two sets must contain all the numbers from both sets, providing they aren't duplicated.
6 and 3
6 and 3. 6x5=30 and 3x10=30
It could be anything that does that to both of them like negative 30. It has to be negative tho
