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2 years ago

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Suzie Spacewalker hovers in space beside a rotating space station in outer space. Both she and the center of mass of the space s

tation are at relative rest. If the space station is in Earth orbit, then Suzie____________

1 answer:

Inga [223]2 years ago

3 0

Answer:

is in the earths orbit

Explanation:

for Suzie to hover in space beside the rotating space station, she and the center of mass of the space station are at relative rest which happens when space station is in Earth orbit, hence she is in the earths orbit.

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Determine whether the given value is a statistic or a parameter. a homeowner measured the voltage supplied to his home on 20 day

Gelneren [198K]

<span>For this example, the value presented would be considered a statistic. The value is a statistic as it represents a numerical measurement of a sample. If it were a parameter, it would need to represent a numerical measurement of a population.</span>

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2 years ago

A bicycle takes 8.0 seconds to accelerate at a constant rate from rest to a speed of 4.0 m/s. If the mass of the bicycle and rid

Inessa05 [86]

Acceleration = (change in speed) / (time for the change)
Acceleration = (4 m/s) / (8 seconds)
Acceleration = 0.5 m/s²

Force = (mass) x (acceleration)
Force = (85 kg) x (0.5 m/s²)
Force = 42.5 Newtons

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2 years ago

Read 2 more answers

Water has a high heat capacity. What does this term mean? a) Water is relatively resistant to an increase in temperature. b) Wat

Delicious77 [7]

Answer:a) Water is relatively resistant to an increase in temperature

Explanation:

Water has relatively high heat capacity i.e. it requires high amount of heat to raise a little increase in temperature.

Heat capacity is defined as ability of molecule to absorb heat . Mathematically heat capacity is defined as

$C=\frac{Q}{\Delta T}$

where $C=heat\ capacity$

$Q=heat\ interaction$

$\Delta T=change\ in\ Temperature$

4 0

3 years ago

A 160cm long string has two adjacent resonance at 85hz frequencies . calculate : 1- the fundamental frequency , 2- the speed of

lara [203]

Length=l=160cm=1.6m

Frequency=85Hz

#1

Fundamental frequency be v

$\\ \sf\bull\longmapsto v=\dfrac{\nu}{2\ell}$

$\\ \sf\bull\longmapsto v=\dfrac{85}{2(1.6)}$

$\\ \sf\bull\longmapsto v=\dfrac{85}{3.2}$

$\\ \sf\bull\longmapsto v=26.6Hz$

#2

First we have to find wavelength

$\\ \sf\bull\longmapsto \lambda=\dfrac{c}{v}$

$\\ \sf\bull\longmapsto \lambda=\dfrac{3\times 10^8ms^{-1}}{26.6}$

$\\ \sf\bull\longmapsto \lambda=0.112\times 10^8m$

$\\ \sf\bull\longmapsto \lambda=112\times 10^5m$

$\\ \sf\bull\longmapsto \lambda=1.12\times 10^6m$

Now..

Velocity be v

$\\ \sf\bull\longmapsto v=f\lambda$

f is frequency

$\\ \sf\bull\longmapsto v=26.5\times1.12\times 10^6m$

$\\ \sf\bull\longmapsto v=29.68\times 10^6$

$\\ \sf\bull\longmapsto v=2.9\times 10^7m/s$

5 0

2 years ago

Before colliding the momentum of block A is +15.0 kg*m/s, and block B is -35.0 kg*m/s. after, block A has a momentum -12.0 kg*m/

UkoKoshka [18]

The momentum of block B afterwards is $-8.0 kg m/s$ .

Explanation:

We can solve this problem by applying the principle of conservation of momentum.

In fact, the total momentum before and after the collision must be conserved. Therefore, we can write:

$p_A + p_B = p_A' + p_B'$

where:

$p_A = +15.0 kg m/s$ is the initial momentum of block A

$p_B = -35.0 kg m/s$ is the initial momentum of block B

$p_A' = -12.0 kg m/s$ is the final momentum of block A

$p_B'$ is the final momentum of block B

Solving for $p_B'$ , we find:

$p_B' = p_A + p_B - p_A' = +15.0 +(-35.0) - (-12.0)=-8.0 kg m/s$

So, the momentum of block B afterwards is $-8.0 kg m/s$ .

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

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2 years ago