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2 years ago

HELP QUICK!! WILL BRAINLIEST

Mathematics

2 answers:

Rina8888 [55]2 years ago

6 0

190 would be the correct answer

solmaris [256]2 years ago

4 0

(5/11)*418=m
m=190

Hope I didn't mess up for your sake.

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What is the value of the expression i 0 × i 1 × i 2 × i 3 × i 4?

astraxan [27]

ANSWER

The value of the expression is
$- 1$

EXPLANATION

Method 1: Rewrite as product of
${i}^{2}$

The expression given to us is,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4}$

We use the fact that
${i}^{2} = - 1$
to simplify the above expression.

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{1} \times {i}^{3} \times {i}^{2} \times {i}^{4}$

This implies,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2}$

We substitute to obtain,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times - 1 \times - 1 \times - 1\times - 1 \times - 1$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times 1 \times 1 \times - 1 = - 1$

Method 2: Use indices to solve.

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0 + 1 + 2 + 3 + 4}$

This implies that,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{10}$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( {{i}^{2}} )^{5}$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( - 1 )^{5} = - 1$

8 0

2 years ago

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3 5/12 as a improper fraction

dimulka [17.4K]

Answer:

41/12

Step-by-step explanation:

3 x 12 = 36 then you add 5 to get 41.

6 0

2 years ago

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A piece of copper tubing is in the shape of a hexagonal prism. The area of the base of the prism is 3 square centimeters. The vo

Evgen [1.6K]

Answer: 17 cm

Step-by-step explanation:

For a regular figure where the area of the base is B, and the height is H, the volume is calculated as:

V = B*H

Here we know that the base of the prism is B = 3 cm^2, and the volume of the prism is 51 cm^3

Then:

B = 3cm^2

V = 51cm^3

If we replace those in the equation above, we get:

51 cm^3 = (3cm^2)*H

Solving this for H gives:

(51 cm^3)/(3 cm^2) = H = 17 cm

The height of the tubing is 17 cm

7 0

2 years ago

How to factor the algebraic expression 24a + 28

bonufazy [111]

So use undistributive properyt]
ab+ac=a(b+c)
so factor 24a dadn 28 to find 'a' the common factor
24=2 times 2 times 2 times 3 tiems a
28=2 times 2 times 7
common one is 2 itmes 2=4
a=4
4(2 times3 times a)+4(7)=4(6a)+4(7)=4(6a+7)

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2 years ago

Find the cosine of ∠W.

d1i1m1o1n [39]

Answer:

ok so u =?? 15 and 17= 2 but cant be cs they 2 4 6 8 10 12 14 16 not 15 or 17so 3

Step-by-step explanation:

5 0

1 year ago

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