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2 years ago

Take away 6 from s and I do not know how to do it

Mathematics

1 answer:

mrs_skeptik [129]2 years ago

8 0

S-6
If you can't figure out the problem again, try thinking of the variable as a number instead

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Use the box plot to complete the sentences

Brrunno [24]

Median- 6
Lower quartile- 3
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2 years ago

Can somebody help me? please

igomit [66]

The answer is A. 2.3^5

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2 years ago

Read 2 more answers

Find the equation of the tangent line to the curve (a lemniscate)

olya-2409 [2.1K]

Answer:

$m=\frac{9}{13}$ and $b=\frac{40}{13}$

Step-by-step explanation:

The equation of curve is

$2(x^2+y^2)^2=25(x^2-y^2)$

We need to find the equation of the tangent line to the curve at the point (-3, 1).

Differentiate with respect to x.

$2[2(x^2+y^2)\frac{d}{dx}(x^2+y^2)]=25(2x-2y\frac{dy}{dx})$

$4(x^2+y^2)(2x+2y\frac{dy}{dx})=25(2x-2y\frac{dy}{dx})$

The point of tangency is (-3,1). It means the slope of tangent is $\frac{dy}{dx}_{(-3,1)}$ .

Substitute x=-3 and y=1 in the above equation.

$4((-3)^2+(1)^2)(2(-3)+2(1)\frac{dy}{dx})=25(2(-3)-2(1)\frac{dy}{dx})$

$40(-6+2\frac{dy}{dx})=25(-6-2\frac{dy}{dx})$

$-240+80\frac{dy}{dx})=-150-50\frac{dy}{dx}$

$80\frac{dy}{dx}+50\frac{dy}{dx}=-150+240$

$130\frac{dy}{dx}=90$

Divide both sides by 130.

$\frac{dy}{dx}=\frac{9}{13}$

If a line passes through a points $(x_1,y_1)$ with slope m, then the point slope form of the line is

$y-y_1=m(x-x_1)$

The slope of tangent line is $\frac{9}{13}$ and it passes through the point (-3,1). So, the equation of tangent is

$y-1=\frac{9}{13}(x-(-3))$

$y-1=\frac{9}{13}(x)+\frac{27}{13}$

Add 1 on both sides.

$y=\frac{9}{13}(x)+\frac{27}{13}+1$

$y=\frac{9}{13}(x)+\frac{40}{13}$

Therefore, $m=\frac{9}{13}$ and $b=\frac{40}{13}$ .

5 0

2 years ago

look that the picture PLSSSS HEELP IM IN A TEST I DID NOT STUDY FOR PLSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS

max2010maxim [7]

Answer:

1. a

2. d

3. c

4. d?

5. cant answer cause I cannot see the data

4 0

2 years ago

If Raj randomly chooses a point in the square below, what is the probability that point is not in the circle? Assume that pi = 3

hodyreva [135]

Answer:

49.7%

Step-by-step explanation:

A cdircle is located within a square.

Area of the circle

Area = $\pi$ $r^{2}$ , where r = 4 units.

Area Circle = 50.3 units^2

Area of the square

Area = l*w or l^2 for a square, since l = w

Area = (10 units)^2

Area = 100 units^2

Area in the square but outside the circle

This is the difference [Square minus Circle Areas]

Square minus Circle Areas = 100 - 50.3 or 49.7 units^2

Probability

The probability of picking a point in the square that is not in the circle is the ration of the two areas: [Outside Circle/Square]x100%

(49.7 units^2)/(100 units^2)x100% = 49.7%

6 0

1 year ago