A 1.26 m aqueous solution of an ionic compound with the formula mx2 has a boiling point of 101.63 ∘c. part a calculate the van't

Question

Cloud [144]

2 years ago

9

A 1.26 m aqueous solution of an ionic compound with the formula mx2 has a boiling point of 101.63 ∘c. part a calculate the van't

hoff factor (i) for mx2 at this concentration. express your answer using two significant figures.

Chemistry

2 answers:

iragen [17] · Answer 1 · 2022-03-30T12:34:27+03:00

iragen [17]2 years ago

6 0

Answer:

The van't hoff factor is 2.49

Explanation:

please look at the solution in the attached Word file

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12345 [234] · Answer 2 · 2022-03-30T10:50:26+03:00

Answer is: Van't Hoff factor (i) for this solution is 1.051 .
Change in boiling point from pure solvent to solution: ΔT =i · Kb · b.
Kb - molal boiling point elevation constant is 0.512°C/m.
b - molality, moles of solute per kilogram of solvent.
b = 1.26 m.
ΔT = 101.63°C - 100°C = 1.63°C.

i = 1.63°C ÷ (0.512°C/m · 1.26 m).

i = 1.051.