1. We assume, that the number 9.375 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 9.375 is 100%, so we can write it down as 9.375=100%.
4. We know, that x is 7.25% of the output value, so we can write it down as x=7.25%.
5. Now we have two simple equations:
1) 9.375=100%
2) x=7.25%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
9.375/x=100%/7.25%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for what is 7.25% of 9.375
9.375/x=100/7.25
(9.375/x)*x=(100/7.25)*x - we multiply both sides of the equation by x
9.375=13.793103448276*x - we divide both sides of the equation by (13.793103448276) to get x
9.375/13.793103448276=x
0.6796875=x
x=0.6796875
now we have:
7.25% of 9.375=0.6796875
Answer:
a = 7.2
Step-by-step explanation:
The figure has been re-labelled and attached to this response.
From the figure, the larger right triangle DAB and the small right triangle BCA are similar. This is because;
i. They have two corresponding congruent angles which are<em> the right angle</em>
and <em>angle B</em>
Therefore, we can say that;
<em>Cross multiply</em>
a x a = 13 x 4
a² = 52
a = √52
a = 7.2
Note: The figure showing the similar triangles has also been attached to this response.
We are given coordinate of K point (7,4).
We need to find the new coordinate of K' point.
Given rule is K' = Ro 270°^(k).
That represents rotation of k 270 degree about the origin.
<em>The rule for rotation of 270 degree about the origin is as following:</em>
<em>(x, y) --------> (y, -x).</em>
Now, applying same rule on point (7,4).
(7,4) -----------> (4,-7).
<h3>Therefore, the coordinates of k' is (4,-7).</h3><h3>Correct option is A. (4,-7).</h3>
Answer:
The new coordinates would be (-4, 11)
(-10, 11) (-9, 7) Hope this helps!
Answer:
false
Step-by-step explanation:
the degree is found by looking at the term with the highest exponent of the variable..
