The sector (shaded segment + triangle) makes up 1/3 of the circle (which is evident from the fact that the labeled arc measures 120° and a full circle measures 360°). The circle has radius 96 cm, so its total area is π (96 cm)² = 9216π cm². The area of the sector is then 1/3 • 9216π cm² = 3072π cm².
The triangle is isosceles since two of its legs coincide with the radius of the circle, and the angle between these sides measures 120°, same as the arc it subtends. If b is the length of the third side in the triangle, then by the law of cosines
b² = 2 • (96 cm)² - 2 (96 cm)² cos(120°) ⇒ b = 96√3 cm
Call b the base of this triangle.
The vertex angle is 120°, so the other two angles have measure θ such that
120° + 2θ = 180°
since the interior angles of any triangle sum to 180°. Solve for θ :
2θ = 60°
θ = 30°
Draw an altitude for the triangle that connects the vertex to the base. This cuts the triangle into two smaller right triangles. Let h be the height of all these triangles. Using some trig, we find
tan(30°) = h / (b/2) ⇒ h = 48 cm
Then the area of the triangle is
1/2 bh = 1/2 • (96√3 cm) • (48 cm) = 2304√3 cm²
and the area of the shaded segment is the difference between the area of the sector and the area of the triangle:
3072π cm² - 2304√3 cm² ≈ 5660.3 cm²
Answer:
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The volume of a cylinder is
(pi) (radius²) (height) .
Radius = 1/2 diameter.
Radius of this pool = (1/2) (18 ft) = 9 ft
The pool is a cylinder with height of 4.5 feet.
The water in it is also a cylinder, but only 4 ft high.
Volume of the water =
(pi) x (radius²) x (height)
= (pi) x (9 ft)² x (4 ft)
= (pi) x (81 ft²) x (4 ft)
= (pi) x (324 ft³) = 1,017.9 ft³ .
Answer:
55555
Step-by-step explanation:
56778654368754775556
Answer:
1 i(sqrt5)
2 7i
3 -9i
4 -64i
5 -5i(sqrt2)
6 -4i(sqrt3)
7 10i(sqrt3)
8 2i(sqrt2)
9 3i(sqrt7)
10 -30i(sqrt2)
Step-by-step explanation:
i is the square root of (-1). We can simplify each one as such.