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2 years ago

Plzzzzz hellllp meeeee plz

Mathematics

2 answers:

gregori [183]2 years ago

6 0

Answer:

(7,5)

Step-by-step explanation:

look at the graph lines, the first number is the x axis, which is the horizontal axis, the second one is the y axis, the vertical line.put your finger at the f and look at x first. you place your finger at the letter F and since the horizontal line is over f, you look at what line it is at .

then you will get 7 thats your first number. But since its reflected you reverse the y and get a positive

Then look at the y axis, put your finger again, then go to the side where the y axis is, since its the bottom part of the y axis, it counts as a negative.

your answer would be (7-5)

iren [92.7K]2 years ago

5 0

Answer:

(7, 5)

Step-by-step explanation:

When reflecting over the x-axis, the only position that moves is the y-coordinate as it is going above the axis it was previously below. Since point F's original position was (7, -5) it is 5 spaces away from the x-axis. We move 5 places up to be even with the x-axis, then move up another 5 places to reflect the point to get F'.

Hope this Helps!

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5) Placido pulls a rope attached to a wagon through a pulley at a rate of q m/s. With dimension as in Figure 5:

Damm [24]

The formula for the speed of the wagon can be found by using Pythagoras theorem, and chain rule of differentiation.

$(a) \ \mathrm{The \ speed \ of \ the \ wagon} , \ \dfrac{dx}{dt} = q -\dfrac{x}{\sqrt{x^2+ 5.76}}$

(b) When x = 0.6 and q = 0.5 m/s, the speed of the wagon is approximately 0.243 m/s.

Reasons:

(a) The distance from the cart to the pulley, r is given by Pythagoras's

theorem as follows;

r = √((3 - 0.6)² + x²) = √(2.4² + x²)

The speed of the wagon = $\mathbf{\dfrac{dx}{dt}}$

The speed of the rope, q = $\mathbf{\dfrac{dr}{dt}}$

By chain rule, we have;

$\dfrac{dr}{dt} = \mathbf{\dfrac{dr}{dx} + \dfrac{dx}{dt}}$

$\dfrac{dr}{dx} = \dfrac{x}{\sqrt{x^2+ 5.76}}$

Therefore;

$\dfrac{dr}{dt} = q =\dfrac{x}{\sqrt{x^2+ 5.76}}+ \dfrac{dx}{dt}$

$\mathrm{The \ speed \ of \ the \ wagon} , \ \dfrac{dx}{dt} = \underline{ q -\dfrac{x}{\sqrt{x^2+ 5.76}}}$

(b) The speed of the wagon when x = 0.6 if q = 0.5 m/s is given as follows;

$\dfrac{dx}{dt} = 0.5 -\dfrac{0.6}{\sqrt{0.6^2+ 5.76}} =\sqrt{\dfrac{1}{17} } \approx 0.243$

The speed of the wagon when x = 0.6 and q = 0.5 m/s, $\dfrac{dx}{dt}$ ≈ 0.243 m/s

Learn more here:

brainly.com/question/17081984

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1 year ago

Use the quadratic formula to solve this equation to 3sf: 5x^2-2x-11=0

Rama09 [41]

X=1/5+2/5√14 or 1/5 + -2/5√14

7 0

2 years ago

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What is the equation of the line with an x-intercept of -1 and a y-intercept of 2? y = 2x - 2 y = - 2x 2 y = 2x 2

guajiro [1.7K]

X intercept = -1, y = 0 (-1, 0)

y intercept = 2, x = 0 (0, 2)

slope between (-1, 0) and (0, 2):

slope = (2 -0)/(0 - -1) = 2/1 = 2, m = 2

Using point (-1, 0) x₁ = -1, y₁ = 0

y - y₁ = m(x - x₁)

y - 0 = 2*(x - -1)

y = 2(x + 1)

y = 2x + 2

6 0

2 years ago

A process of inserting points between actual plotted data points or extending an actual line of data is called:

german

The correct answer is:

interpolating

Explanation:

Interpolation is a method of constructing new data points within the range of a discrete set of known data points.

This would include inserting data points between two known points and extending a data set.

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2 years ago

Find parametric equations for the line through the point (0, 2, 2) that is parallel to the plane x + y + z = 4 and perpendicular

Oxana [17]

Answer: X = 3t, Y =2 - t, Z =2

Step-by-step explanation: the plane

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M =<1,1,1> and the line

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v =<1, −1, 2>. So the vector

A= n × v

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=<2−(−1),1−2,−1−1>

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3 years ago