2 years ago

Point J is located at (3,3) and point K is located at (7,-5) Find the midpoint of the line segment JK

Mathematics

1 answer:

bazaltina [42]2 years ago

8 0

Answer:

(5, -1)

Step-by-step explanation:

To get the midpoint, You just need to find the average between both X and Y coordinates. In this case, X is (3 + 7) / 2 and Y is (3 + -5) / 2.

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Find the mean, Find the median, mode, and range of each Data set 46, 35, 23, 37, 29, 53, 43

g100num [7]

Answer: mean- 38

median- 37

mode- no mode

range- 30

Step-by-step explanation:

5 0

2 years ago

Subtract. 23.87 - 1.12 A. 13.75 B. 22.75 C. 24.99 D. 12.67

Shtirlitz [24]

Answer:

B. 22.75

Step-by-step explanation:

23.87

- 1.12

22.75

7 0

2 years ago

Read 2 more answers

What is the volume of this?

Oksanka [162]

Answer:

82 in^3

Step-by-step explanation:

3 x 2 x 7 + 2 x 2 x 10 = 82 in^3

7 0

1 year ago

Click the photo )) give three numbers between -7 and 9 that satisfy the given condition.

Veronika [31]

13 3/39 is too big, it's greater than 9, so that one is out.
16 is an integer, so that one is out too. 99/6 = 16.5, which is greater than 9, so it can't be right

So the answer is the other 3

6 0

2 years ago

the strength of students in a school when increased by 8% becomes 2160. find the original strength of students in the school.

Leni [432]

Answer:

1987.2

Step-by-step explanation:

We can write a proportion to find the total amount in the choir using the information given. A proportion is two equivalent ratios set equal to each other. Since we know the strength of students increased by 8% to 2160 then the original was 92%.

$\frac{92}{100}=\frac{y}{2160}$

We will cross multiply the numerator of one ratio with denominator of the other. And then solve for y.

92(2160)=100(y)

198720=100y

y=1987.2

There are 1987.2 as the original strength of students.

6 0

2 years ago