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2 years ago

If 4 is subtracted from twice a number, the result is 10 less than the number. Find the number. *

Mathematics

2 answers:

motikmotik2 years ago

8 0

Answer:

the answer is -6

Step-by-step explanation:

drek231 [11]2 years ago

8 0

Answer:

x =-6

Step-by-step explanation:

Let the unknown number be x

$2(x)-4=x-10\\\\2x -4=x-10\\\\\mathrm{Add\:}4\mathrm{\:to\:both\:sides}\\2x-4+4=x-10+4\\\\Simplify\\2x=x-6\\\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\2x-x=x-6-x\\\\Simplify\\x=-6$

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A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times.

tatyana61 [14]

Answer:

(a) $g(n)=0.05\cdot 2^n$

(b) $g^{-1}(n)=\log_{2}20g(n)$

Step-by-step explanation:

Part A

The paper's thickness = 0.05mm

When the paper is folded, its width doubles (increases by 100%).

The thickness of the paper grows exponentially and can be modeled by the function:

$g(n)=0.05(1+100\%)^n\\\\g(n)=0.05\cdot 2^n$

Part B

$g(n)=0.05\cdot 2^n\\2^n=\dfrac{g(n)}{0.05}\\ 2^n=20g(n)\\$Changing to logarithm form, we have:\\\log_{2}20g(n)=n\\$Therefore:\\g^{-1}(n)=\log_{2}20g(n)$

Part C

If the thickness of the paper, g(n)=384,472,300,000 mm

Then:

$g^{-1}(n)=\log_{2}20g(n)\\g^{-1}(n)=\log_{2}20\times 384,472,300,000\\=\dfrac{\log 20\times 384,472,300,000}{\log 2} \\g^{-1}(n)=42.8 \approx 43\\n=43$

You must fold the paper 43 times to make the folded paper have a thickness that is the same as the distance from the earth to the moon.

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