Answer:
The probability that a call last between 4.2 and 4.9 minutes is 0.4599
Step-by-step explanation:
Let X be the length in minutes of a random phone call. X is a normal distribution with mean λ=4.2 and standard deviation σ=0.4. We want to know P(4.2 < X < 4.9). In order to make computations, we will use W, the standarization of X, given by the following formula
We will use 
, the cummulative distribution function of W. The values of are well known and the can be found in the attached file
We conclude that the probability that a call last between 4.2 and 4.9 minutes is 0.4599
Answer:34.17
Step-by-step explanation:
(-102.5) ➗ (-3)=34.17
Answer:
Step-by-step explanation:
use
i=prt
i=interest
p= principal value
r=rate
t=time
now you want to find time then it will be
t= i/pr
put values
t= 3722/(2000*7.6%)
t= 2 years
calculation is in fraction but your question given you annual interest so time will also be 2 years not in months
Answer:
And if we count the number of zeros before the number 7, we can rewrite the number like this:
We cansolve this problem also counting the number of positions that we need to move the decimal point to the right in order to obtain the first number (7)
And the best option would be:
B. 7 x 10-7
Step-by-step explanation:
For this case we have the following number given:
And if we count the number of zeros before the number 7, we can rewrite the number like this:
We cansolve this problem also counting the number of positions that we need to move the decimal point to the right in order to obtain the first number (7)
And the best option would be:
B. 7 x 10-7
Answer:
2
Step-by-step explanation:
