Answer:
0.197 M
Explanation:
The reaction equation is:
H2SO4(aq) +2KOH(aq) ----> K2SO4(aq) + 2H2O(l)
number of moles of H2SO4 = 0.25 L * 0.45 M = 0.1125 moles
number of moles of KOH = 0.2 L * 0.24 M = 0.048 moles
since H2SO4 is the reactant in excess;
2 moles of KOH reacts with 1 mole of H2SO4
0.048 moles of KOH reacts with 0.048 * 1/2 = 0.024 moles of H2SO4
Amount of excess H2SO4 left unreacted = 0.1125 - 0.024 = 0.0885 moles
Total volume = 0.25 L+ 0.2 L = 0.45 L
concentration of H2SO4 = 0.0885/0.45 = 0.197 M
