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2 years ago

Do number 7 and 8 please

Mathematics

1 answer:

Kruka [31]2 years ago

5 0

7) $\sqrt[3]{64} = \sqrt[3]{4^3} = 4$

8) $\sqrt[3]{216} = \sqrt[3]{6^3} = 6$

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I need help with this!!

ddd [48]

The answer is answer choice 3

5 0

2 years ago

Find an equation that models the path of a satellite if its path is a hyperbola, a = 55,000 km, and c= 81,000 km. Assume the cen

elena-14-01-66 [18.8K]

Answer:

$\frac{x^2}{55000^2} - \frac{y^2}{59464^2} =1$

Step-by-step explanation:

the transverse axis is horizontal.

so its a horizontal hyperbola

Center is the origin so center is (0,0)

Equation of horizontal hyperbola is

$\frac{x^2}{a^2} - \frac{y^2}{b^2} =1$

Given a= 55000 and c= 81000

c^2 = a^2 + b^2

81000^2 = 55000^2 + b^2

subtract 55000^2 on both sides

b = sqrt(81000^2 - 55000^2)= 59464.27

now plug in the values

$\frac{x^2}{55000^2} - \frac{y^2}{59464^2} =1$

7 0

2 years ago

Which expression is equivalent to -<br>60x20, 24<br>30x10 12?

hoa [83]

Answer:

30x10 12

Step-by-step explanation:

6 0

2 years ago

Given the system of equations presented here:

Nata [24]

2x + 4y = 14
4x + y = 20......multiply by -4
----------------
2x + 4y = 14
-16x - 4y = -80 (result of multiplying by -4)
---------------add
-14x = -66....as u can see, ur y's cancel out

so ur answer is : 1st answer choice <==

** and just so u know, u could have multiplied the 1st equation by -2, and it would have cancelled out ur x's

6 0

2 years ago

In the figure, OA is a diameter of the smaller circle and O is the centre of the larger circle. Find the

Burka [1]

Answer:

942 6/7 cm²

Step-by-step explanation:

Since O = Center of bigger circle, OA = Radius of bigger circle.

∴ Area of smaller circle - Area of bigger circle = Area of shaded part.

∴ Area of smaller circle = 22/7 × 10²

= 22/7 × 100

= 2200/7

= 314 2/7 cm²

∴ Area of bigger circle = 22/7 × 20 ²

= 22/7 × 400

= 1257 1/7 cm²

∴ Area of shaded part = 1257 1/7 - 314 2/7

= 942 6/7 cm²

5 0

2 years ago