Answer:
31,41,51,71
Step-by-step explanation:
Statement:
1. RS tangent to Circle A and Circle B at points R and S
2. AR ⊥ RS, BS ⊥ RS
3. AR ║ BS
Reason:
1. Given
2. Radius ⊥ to tangent
3. 2 lines ⊥ to same line are ║
100% Correct
~Hope it helps~ :)
Answer:
may be 13 I hope this is the right answer
Answer:
3.14 = pi
1.) R = 1.5 and A = 7.065
2.) D = 28 and A = 615.44
3.) R = 10 and A = 314
Step-by-step explanation:
R = 0.5×d
Area of circle = π×r²
Answer:
-2, 8/3
Step-by-step explanation:
You can consider the area to be that of a trapezoid with parallel bases f(a) and f(4), and width (4-a). The area of that trapezoid is ...
A = (1/2)(f(a) +f(4))(4 -a)
= (1/2)((3a -1) +(3·4 -1))(4 -a)
= (1/2)(3a +10)(4 -a)
We want this area to be 12, so we can substitute that value for A and solve for "a".
12 = (1/2)(3a +10)(4 -a)
24 = (3a +10)(4 -a) = -3a² +2a +40
3a² -2a -16 = 0 . . . . . . subtract the right side
(3a -8)(a +2) = 0 . . . . . factor
Values of "a" that make these factors zero are ...
a = 8/3, a = -2
The values of "a" that make the area under the curve equal to 12 are -2 and 8/3.
_____
<em>Alternate solution</em>
The attachment shows a solution using the numerical integration function of a graphing calculator. The area under the curve of function f(x) on the interval [a, 4] is the integral of f(x) on that interval. Perhaps confusingly, we have called that area f(a). As we have seen above, the area is a quadratic function of "a". I find it convenient to use a calculator's functions to solve problems like this where possible.