Height of the woman = 5 ft
Rate at which the woman is walking = 7.5 ft/sec
Let us assume the length of the shadow = s
Le us assume the <span>distance of the woman's feet from the base of the streetlight = x
</span>Then
s/5 = (s + x)/12
12s = 5s + 5x
7s = 5x
s = (5/7)x
Now let us differentiate with respect to t
ds/dt = (5/7)(dx/dt)
We already know that dx/dt = 7/2 ft/sec
Then
ds/dt = (5/7) * (7/2)
= (5/2)
= 2.5 ft/sec
From the above deduction, it can be easily concluded that the rate at which the tip of her shadow is moving is 2.5 ft/sec.
Answer:
=
Step-by-step explanation:
Ⓗⓘ ⓣⓗⓔⓡⓔ
Well, assuming m of angle ABD is 90 degrees, then you would add and then solve.
2x+14+x+7=90
3x+21=90
3x=69
=
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, !
Answer:
-8 + 14n
Step-by-step explanation:
-2(4-4n)+6n
Distribute the -2
-8 +8n+6n
Combine like terms
-8 + 14n