Answer:
<em>Her speed driving in nice weather is 50 mph and in thunderstorm is 32 mph.</em>
Step-by-step explanation:
Barbara drives 50 miles in clear weather and then encounters a thunderstorm for the last 16 miles.
Suppose, her speed in nice weather is mph.
As she drives 18 mph slower through the thunderstorm than she does in clear weather, so her speed in thunderstorm will be:
<u>We know that,</u>
So, <u>the time of driving in clear weather</u> hours
and <u>the time of driving in thunderstorm</u> hours.
Given that, <u>the total time for the trip is 1.5 hours</u>. So, the equation will be......
Using zero-product property.........
<em>We need to ignore here, otherwise the speed in thunderstorm will become negative.</em>
So, her speed driving in nice weather is 50 mph and her speed driving in thunderstorm is (50-18) = 32 mph
Step-by-step explanation:
So in the equation given, y = 2x - 3
you substitute x for whats given in the table in the x column.
Example
In the graph the first number under the x colum is -1.
y = 2x - 3 in the equation you take out x and put -1.
So now the equation becomes y = 2 × -1 - 3.
Using bedmas to solve the question you should get -5
Which now means y = -5
To plot the point now x would be -1 and y would be -5 (-1, -5)
Same thing for the second number in the x Column.
y = 2 × 1 - 3 which equals -1
To plot it
x = 1 y = -1. (1, -1)
And for the last number 3.
Agai. You substitute x for 3 which makes the equation y = 2 × 3 - 3
this gives you 3 and to plot it
x would be 3 and y would be 3
6 = 5r - 14
6 + 14 = 5r
20 = 5r
r = 4
Well there both even numbers so the gcf factor would have to be even also
60 = 1,2,3,4,5,6,10,12,15,20,30,60
72 = 1,2,3,4,6,8,9,12,18,24,36,72
The Gcf would be 12
So using a calculator this question is really easy 125,000x 1.35 ^10 =.
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