1. A boat initially moving at 10 m/s accelerates at 2 m/s2 for 10 s. What is the velocity of the boat after 10 seconds?

1. If an object on a horizontal frictionless surface is attached to a spring, displaced, and then released. It will oscillate. I

AURORKA [14]

Answer: a) 0.12m; b) 1,6 s; c) 0.625 1/s

Explanation: The simple harmonic movement can be described by a sin or cosine function in time.

This can be in the form:

X(t)= A Sin/Cos (wt+φ) where φ is initial phase o position at t=0

w the angular frequency are related to the frequency (f) as 2Pif

and f=1/T period of oscillating

3 0

2 years ago

When a box of chocolate bars is in mechanical equilibrium, what can be correctly said about all the forces that act on it?

rjkz [21]

Answer:

All the forces are opposite and equal and will give net force zero.

Explanation:

Mechanical equilibrium is the equilibrium in which the total force on the system is zero means the system is neither accelerated nor any kind of torque on the system.

The mechanical system can also be defined as the equal forces are applied in opposite direction in a system which cancels out all the forces, will give net force zero.

Therefore, when a box of chocolate bars is in mechanical equilibrium all the forces in this system are equal and the opposite which balances each other will give net force zero.

3 0

2 years ago

A car came to a stop from a speed of 35 m/s in a time of 8.1 seconds. What was the acceleration of the car?

uranmaximum [27]

Simply subtract the two velocities and divide by 8.1,

$\frac{0 - 35}{8.1} = - 4.32$

~~

I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey

5 0

2 years ago

Read 2 more answers

A position-time graph is shown below:

ikadub [295]

Answer: The object moves forward at 5 m/s, stops, and then changes velocity.

Explanation:

With the information given in the question we can graph the points (image attached).

As we can observe, in the first segment of the graph the velocity is increasing linearly (at a constant rate) and is 5 m/s, then in the second segment we can see the position of the object remains the same from second 2 to second 4, which means the object is stopped.

Finally, in the third and last segment, we can observe a change in velocity (at a negative constant rate, because is decreasing), which is decreasing until the object stops.

7 0

2 years ago

(Assume there is no friction) A bike starts rolling down a hill at 4.3 m/s . After 12 s it reaches the bottom moving at 11.5 m/s

mote1985 [20]

Answer:

94.8 m

Explanation:

The motion of the bike is a uniformly accelerated motion (=constant acceleration), so we can use the following suvat equation:

$s=(\frac{u+v}{2})t$

where:

s is the distance covered

u is the initial velocity

v is the final velocity

t is the time elapsed

For the bike in this problem, we have:

u = 4.3 m/s is the initial velocity

v = 11.5 m/s is the final velocity

t = 12 s is the time

Solving for s, we find the length of the hill:

$s=(\frac{4.3+11.5}{2})(12)=94.8 m$

8 0

2 years ago

1. A boat initially moving at 10 m/s accelerates at 2 m/s2 for 10 s. What is the velocity of the boat after 10 seconds?​

1. A boat initially moving at 10 m/s accelerates at 2 m/s2 for 10 s. What is the velocity of the boat after 10 seconds?