In three dimensions, the cross product of two vectors is defined as shown below
Then, solving the determinant
In our case,
Where we used the formula for AxB to calculate ixj.
Finally,
Thus, (i+j)x(ixj)=i-j
Answer: The correct answer is B.
Step-by-step explanation: To simplify a square root, you take the factors of the value in the square root and see the greatest factor that is a square. In this case, 49 is the greatest square factor of 98. You take the square root of 49, which is 7. 7 goes outside the radicand. Leave 2 inside the radical because 49 x 2 = 98. Hence, the correct answer is B.
Answer:
students' ratings of their professors' performance on a five-point scale ranging from poor to excellent
Step-by-step explanation:
There are four type of scales in mathematics. They include:
1. Nominal scale : they do not measure quantity. they are used to classify a population into two or more scales that are exhaustive and mutually exclusive. e.g. classifying a population based on gender, naming the different car brands seen in a school's parking lot
2. Ordinal scale : this scale measures ranks a population from best to worst or from least to most. e.g. ranking the participants of a race based on their performance
3. Interval scale : this scale has the property of order and equal intervals. Zero is not meaningful.
Interval scale is used when the difference between the numbers are meaningful. e.g. students' ratings of their professors' performance on a five-point scale ranging from poor to excellent Here a child who is scored 1, did very poorly and a child scored 5, performed excellently well.
4. Ratio scale : this scale has the property of order, a meaningful zero and equal intervals.
Sorry wish I could help but I need to see the picture to answer the question. Sorry :-(
Answer:
1.
y = 20(11) + 300 = 520
y = 5(11)(11) = 605
y = 10(1.4)^11 = 404.96
hence the quadratic formula - y = 5x^2 has the largest y-value
2.
y = 20 (14) + 300 = 580
y = 5 (14) (14) = 980
y = 10(1.4)^ 14 = 1111.20 > this is greater than both equations above
14 is the smallest value of x for which the value of the exponential equation is greater than the values of both the linear and quadratic functions
Step-by-step explanation: