2 years ago

Sines/cosines please help!!!!

Mathematics

1 answer:

AleksandrR [38]2 years ago

8 0

I can help explain it if you PM me.

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2 years ago

Complete the square to transform the quadratic equation into the form (x – p)2 = q.

ryzh [129]

The transformed equation is:

$(x-3)^2 = 23$

Step-by-step explanation:

We have to convert the equation in the form

$(x-p)^2 = q$

Given equation is:

$x^2-6x-8 = 6$

Adding 8 on both sides

$x^2-6x-8+8 = 6+8\\x^2-6x = 14$

In the given equation

a = x

b= ?

So,

$2.x.b = 6x\\b =\frac{6x}{2x}\\b = 3\\$

So 3^2 will be added on both sides

$(x)^2-6x+ (3) = 14+ (3)^2\\(x-3)^2 = 14+9\\(x-3)^2 = 23$

Hence,

The transformed equation is:

$(x-3)^2 = 23$

Keywords: Quadratic equation, transformation

Learn more about quadratic equation at:

#LearnwithBrainly

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2 years ago

Im so confused on this please help if you can..

Archy [21]

It's been a while since I have done these kind of questions, but I would say a 180 transformation would be my best answer. Hope this helps a bit!

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