Answer:
The puck moves a vertical height of 2.6 cm before stopping
Explanation:
As the puck is accelerated by the spring, the kinetic energy of the puck equals the elastic potential energy of the spring.
So, 1/2mv² = 1/2kx² where m = mass of puck = 39.2 g = 0.0392 g, v = velocity of puck, k = spring constant = 59 N/m and x = compression of spring = 1.3 cm = 0.013 cm.
Now, since the puck has an initial velocity, v before it slides up the inclined surface, its loss in kinetic energy equals its gain in potential energy before it stops. So
1/2mv² = mgh where h = vertical height puck moves and g = acceleration due to gravity = 9.8 m/s².
Substituting the kinetic energy of the puck for the potential energy of the spring, we have
1/2kx² = mgh
h = kx²/2mg
= 59 N/m × (0.013 m)²/(0.0392 kg × 9.8 m/s²)
= 0.009971 Nm/0.38416 N
= 0.0259 m
= 2.59 cm
≅ 2.6 cm
So the puck moves a vertical height of 2.6 cm before stopping
The amplitude did not change when the recurrence was expanded on the grounds that the long headstrong time of the heart forestalls adjustment. It is the most extreme removal or separation moved by a point on a vibrating body or wave measured from its balance position. It is equivalent to the one-a large portion of the length of the vibration way.
The acceleration of this car is equal to 5 .
<u>Given the following data:</u>
- Initial velocity = 0 m/s (assuming it's starting from rest).
To determine the acceleration of this car:
<h3>How to calculate acceleration.</h3>
In Science, the acceleration of an object is calculated by subtracting the initial velocity from its final velocity and dividing by the time.
Mathematically, acceleration is given by this formula:
<u>Where:</u>
- U is the initial velocity.
- is the time measured in seconds.
Substituting the given parameters into the formula, we have;
Acceleration, a = 5
Read more on acceleration here: brainly.com/question/24728358
F = q₁q₂C / r²
F force
q charge
C Coulomb constant
r separation between charges
Answer:
12 units
Explanation:
This problem can be solved if we take into account the equation for a sphere
where we took that the radius is 13 units. If we take z=5 and we replace this value in the equation of the sphere we have
where we have taken x2 +y2 because if the equation of a circunference.
In this case the intersection is made when we take z=5, for this value the sphere and the plane coincides in values.
Hence, the radius is 12 units
I hope this is useful for you
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