False. A reflection over the y-axis would result in: (-8,5)
The work done in pushing the box is 64000 lb-ft²/s²
<h3>How to calculate the work done by the person?</h3>
Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is
W = mgh where
- m = mass of box = 40 lb,
- g = acceleration due to gravity = 32 ft/s² and
- h = height of incline = LsinФ where
- L = length of incline = 100 ft and
- Ф = angle of incline = 30°
So, W = mgh
W = mgLsinФ
So, substituting the values of the variables into the equation, we have
W = mgLsinФ
W = 40 lb × 32 ft/s² × 100 ftsin30°
W = 1280 lb-ft/s² × 100 ft × 0.5
W = 1280 lb-ft/s² × 50 ft
W = 64000 lb-ft²/s²
So, the work done in pushing the box is 64000 lb-ft²/s²
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-54 i think is the answer
Answer:
The chosen topic is not meant for use with this type of problem. Try the examples below.
√x+2=3
−4+y=3y+4(y−3)
2+|3x|=2+3
Answer:
k=7
Step-by-step explanation:
first, plug in the given values
2x+3y=k --> 2(2)+3(1)=k
-->4+3=k
-->7=k
k=7
