Answer:
C5H5N is the base and C5H5NH+ is the conjugate acid
H2O is the acid and OH− is the conjugate base
Explanation:
<u>Hydrogen + is also called a proton</u>
C5H5N is the base because it receives the proton (H+) and C5H5NH+ is its conjugate acid
H2O is the acid because it gives up the proton and OH− is the conjugate base because it is capable of receiving the proton
Answer:
HNO3 is the acid and NO3- is the conjugate base
H2O is the base and H3O+ is the conjugate acid
Explanation
HNO3 is the acid and NO3− is its conjugate base, capable of receiving a proton
H2O is the base because it receives the proton and H3O+ is a conjugate acid capable of giving up the proton.
Answer:
643g of methane will there be in the room
Explanation:
To solve this question we must, as first, find the volume of methane after 1h = 3600s. With the volume we can find the moles of methane using PV = nRT -<em>Assuming STP-</em>. With the moles and the molar mass of methane (16g/mol) we can find the mass of methane gas after 1 hour as follows:
<em>Volume Methane:</em>
3600s * (0.25L / s) = 900L Methane
<em>Moles methane:</em>
PV = nRT; PV / RT = n
<em>Where P = 1atm at STP, V is volume = 900L; R is gas constant = 0.082atmL/molK; T is absolute temperature = 273.15K at sTP</em>
Replacing:
PV / RT = n
1atm*900L / 0.082atmL/molK*273.15 = n
n = 40.18mol methane
<em>Mass methane:</em>
40.18 moles * (16g/mol) =
<h3>643g of methane will there be in the room</h3>
Answer : The amount of formaldehyde permissible are,
Explanation : Given,
Density of air =
First we have to calculate the mass of air.
Now we have to calculate the amount of formaldehyde.
Permissible exposure level of formaldehyde = 0.75 ppm =
Amount of formaldehyde in 7.2 g of formaldehyde =
Amount of formaldehyde in 7.2 g of formaldehyde =
Thus, the amount of formaldehyde permissible are,