The more reasonable measurement of the distance between the tracks on a CD is 1.6 ⋅ 10^-3 mm. This is also equal to 0.0016mm. <span>1.6 ⋅ 10^3 mm is too large for a CD track</span>
Answer:
5 packs of markers and 2 packs of crayons
Step-by-step explanation:
they will both have 50
The 4th term of the sequence can be determined as,
Thus, option (b) is correct.
400/12 = # of dozen needed
.89 * # of dozen needed
400/12=33.33 need 34 dozen
.89*34=$30.26
Answer:
234567
Step-by-step explanation: