The square root of 25 would be 5!
Brainliest please? I am trying to get my rank to ace!
Set f(b) = b^2 - 75 = to 0 and solve for b:
b^2 = 75
b^2 = 25(3)
b = plus or minus sqrt(25[3]) = plus or minus sqrt(25)*sqrt(3) = plus or minus 5 sqrt(3).
Answer:
x-int: 2
y-int: -2
Step-by-step explanation:
x-int is where the line crosses the x axis (horizontal line) and y-int is where the line crosses the y axis (vertical line).