Missing question: <span>Assume a density of 10.35 g/cm3 for Ag, A(Ag) = 107.87 g/mol.
N(Ag) = Na </span>· d(Ag) ÷ A(Ag).
N(Ag) = 6,023·10²³ atoms/mol · 10,35 g/cm³ · 10⁶ cm³/m³ ÷ 107,87 g/mol.
N(Ag) = 5,78·10²⁸ atoms/mol.
Nv = 5,78·10²⁸ atoms/mol · 5·10⁻⁵.
Nv = 2,89·10²².
Answer:
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Explanation:
Answer: PV = nRT
A gas at STP... This means that the temperature is 0°C and pressure is 1 atm.
R is the gas constant which is 0.08206 L*atm/(K*mol)
Rearranging for volume
V = nRT/P
The temperature and number of moles are held constant. This means that this uses Boyle's Law. (The ideal gas law could be manipulated to give us this result when T and n are held constant.)
PV = k
where k is a constant.
This means that
P₁V₁ = k = P₂V₂
P₁V₁ = P₂V₂
(1 atm) * (1 L) = (2 atm) * V₂
V₂ = 0.5 L
The new volume of the gas is 0.5 L.
Explanation:
Answer:
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Explanation:
