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2 years ago

Assume we have 25 mL of a 2.5 M HCl and a solution of NaOH of unkown concentration. The two react via the following equation.

Chemistry

1 answer:

navik [9.2K]2 years ago

6 0

Answer is A - HCl is the titrant and D-NaOH is the analyte.

In a titration process, the solution of unknown concentration considered is the analyte. During titration, a standard solution(titrant) is added to an analyte until the equivalence point is achieved.

So in this case as the concentration of NaOH is not known,NaOH is the analyte.

Titrant is the solution whose concentration is known to us and is added to an analyte until the equivalence point is reached. In this case since we know the concentration of HCl, HCl is the titrant.

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Sonbull [250]

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KatRina [158]

Answer:

1.03 atm

Explanation:

Primero convertimos 21 °C y 37 °C a K:

21 °C + 273.16 = 294.16 K

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Una vez tenemos las temperaturas absolutas, podemos resolver este problema usando la ley de Gay-Lussac:

T₁P₂ = T₂P₁

En este caso:

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Y despejando P₂:

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2 years ago

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Explanation:

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