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2 years ago

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The distance from Michaels house to his Granma house is 84 miles round trip . If Michael visits his granma 9 times each year how

many miles does he travel to and from his grandmas each year.

2 answers:

kvv77 [185]2 years ago

4 0

Answer:

Michael travels a total of 756 miles each year.

Step-by-step explanation:

If you want the total number of miles he travels(to and from the house combined), just multiply 84 by 9.

84 x 9 = 756

prohojiy [21]2 years ago

4 0

Answer:

Step-by-step explanation:

Michael travels a total of 756 miles each year.

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A bag contains some white and black balls . The probability of picking two white balls one after other without replacement from

FromTheMoon [43]

Answer:

2/35

Step-by-step explanation:

Let w and b be the numbers of white and black balls in the bag respectively.

So, the total numbers of the balls in the bag is

$n=w+b\;\cdots(i)$

As the bag can hold maximum 15 balls only, so

$n\leq15 \;\cdots(ii)$

Probability of picking two white balls one after other without replacement

=Probability of the first ball to be white and the probability of second ball to be white

=(Probability of picking first white balls) x( Probability of picking 2nd white ball)

Here, the probability of picking the first white ball $=\frac{w}{n}$

After picking the first ball, the remaining

white ball in the bag $= w-1$

and the remaining total balls in the bag $=n-1$

So, the probability of picking the second white ball $=\frac{w-1}{n-1}$

Given that, the probability of picking two white balls one after other without replacement is 14/33.

$\Rightarrow \frac{w}{n} \times \frac{w-1}{n-1}=\frac{14}{33}$

$\Rightarrow \frac{w(w-1)}{n(n-1)} =\frac{14}{33}$

Here, $w$ and $n$ are counting numbers (integers) and 14 and 33 are co-primes.

Let, $\alpha$ be the common factor of the numbers $w(w-1)$ (numerator) and $n(n-1)$ (denominator), so

$\frac{w(w-1)}{n(n-1)} =\frac{14\alpha}{33\alpha}$

$\Rightarrow w(w-1)=14\alpha\cdots(iii)$

And $n(n-1)=33\alpha.$

As from eq. (ii), $n\leq 15$ , so, the possible value of $\alpha$ for which multiplication od two consecutive positive integers (n and n-1) is $33\alpha$ is 4.

$n(n-1)=11\times (3\alpha)$

$\Rightarrow n(n-1)=12\times11$ [as $\alpha=4$ ]

$\Rightarrow n=12$

So, the number of total balls =12

From equation (iv)

$w(w-1)=7\times (2\alpha)$

$\Rightarrow w(w-1)=8\times7$

$\Rightarrow w=8$

So, the number of white balls =8

From equations (i), the number of black balls =12-8=4

In the similar way, the required probability of picking two black balls one after other in the same way (i.e without replacement) is

$=\frac{b}{n} \times \frac{b-1}{n-1}$

$= \frac{4}{15} \times \frac{4-1}{15-1}$

$= \frac{4}{15} \times \frac{3}{14}$

$= \frac{2}{35}$

probability of picking two black balls one after other without replacement is 2/35.

6 0

2 years ago

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar. A medical center o

viktelen [127]

Answer:

1) 0.1504

2) 0.432

Step-by-step explanation:

1) The given information are;

The proportion of the morning appointments that are with elderly patients = 60%

The number of patients in the appointments = 10 patients

The proportion of the morning appointments that are with non-elderly patients = 100 - 60 = 40%

The binomial probability distribution is given as follows;

$P(X = r) = \dbinom{n}{r}p^{r}\left (1-p \right )^{n-r}$

$P(X = 0) = \dbinom{10}{0}0.6^{0}\left (1-0.6 \right )^{10}$ = 0.000105

$P(X = 1) = \dbinom{10}{1}0.6^{1}\left (1-0.6 \right )^{9}$ = 0.0016

$P(X = 2) = \dbinom{10}{2}0.6^{2}\left (1-0.6 \right )^{8}$ = 0.01062

$P(X = 3) = \dbinom{10}{3}0.6^{3}\left (1-0.6 \right )^{7}$ = 0.0425

The probability that the first four patients are elderly is 0.000105 + 0.0016 + 0.1062 + 0.0425 = 0.1504

2) The probability that exactly 2 out of 3 morning patients are elderly patient is given as follows

$P(X = 2) = \dbinom{3}{2}0.6^{2}\left (1-0.6 \right )^{1}$ = 0.432

8 0

2 years ago

What is 5.25 divided by 0.75

Novay_Z [31]

5.25 divided by 0.75 is 7.

5 0

2 years ago

Read 2 more answers

If ABCD is a rectangle, calculate x as a function of α

Yanka [14]

Answer:

Step-by-step explanation:

The length of this triangle is 10 squares

and the width is 4 squares

The diagonals divide the rectangle into four triangles

These traingles are isoceles

Each two triangles facing each others are identical

<B = 90 degree

B = alpha + Beta

Let Beta be the angle next alpha

The segment that is crossing Beta is its bisector since it perpendicular to the diagonals wich means that:

Beta = 2x

Then B = alpha + 2x

90 = alpha +2x

90-alpha = 2x

x = (90-alpha)/2

4 0

2 years ago

Read 2 more answers

how many meters are equal to 5,253 centimeters? use how the placement of the decimal point changes when dividing by power of 10

motikmotik

Answer:

$52.53\ \text{meters}$

Step-by-step explanation:

$1\ \text{meter}=100\ \text{centimeter}$

$1\ \text{centimeter}=\dfrac{1}{100}\ \text{meter}$

In the question the quantity that is required to be converted to meters is 5253 centimeters.

$5253\ \text{cm}=5253\times \dfrac{1}{100}\\ =52.53\ \text{meters}$

So, the required measurement in meters is $52.53\ \text{meters}$ .

3 0

2 years ago