Help please.........
1 answer:
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First, think this through. If you are 23 miles from Sacramento, and 110 miles from Oakland (I am assuming it is miles since you didn't specify *cough cough*) then the two cities are 133 miles apart (also assuming you are in between them)
so, we use the midpoint formula to find our position
and get 66.5 miles from both Sacramento and Oakland.
Next, we already know the sign is 23 miles away from Sacramento so we can use that distance and our position to figure out how far away the sign is. We use absolute values because distance is always positive.
so we get
to double check, use the sign's distance from Oakland.
so, we are 43.5 miles from the sign!
hope this helps
so, we use the midpoint formula to find our position
and get 66.5 miles from both Sacramento and Oakland.
Next, we already know the sign is 23 miles away from Sacramento so we can use that distance and our position to figure out how far away the sign is. We use absolute values because distance is always positive.
so we get
to double check, use the sign's distance from Oakland.
so, we are 43.5 miles from the sign!
hope this helps
Answer:
g(t) = 10000(0.938)^t
Step-by-step explanation:
Given data:
car worth is $10,000 in 2012
car worth is $8000 in 2014
let linear function is given as
P(t) = at + b
which denote the value of car in year t
take t =0 for year 2012
at t =0, 10,000 = 0 + b
we get b = 10,000
take t =2 for year 2014
at t =2, P(2) = 2a + b
8800 = 2a + 10,000
a = - 600
Thus the price of car at year t after 2012 is given as p(t) = -600t + 10000
let the exponential function where t denote t = 0 at 2012
putting t = 0 P(0) = 10,000 we get 10,000 = ab^0
a = 10,000
putting t = 2 p = 8800
b = 0.938
g(t) = 10000(0.938)^t