Answer:
v = 25 m / s
Explanation:
For this exercise we use the relations and kinematics
first part, the train accelerates from v₀ = 7.0 m/s to 13 m/s in a time t = 8.0 s
v = v₀ + a t
a =
a =
a = 0.75 m / s²
second part. Accelerate again for t = 16 s
v = v₁ + a t
for this interval the initial velocity is v₁ = 13 m / s
v = 13 + 0.75 16
v = 25 m / s
The answer is c. velocity
The trick here is that there are two variables, Diameter of the coil and number of turns in it. So, in order to solve it, we will need two equations in D and N
Since we are making coil, formula for magnetic field will be B = μₒni/D
D = μₒni/B = 4π x 10^(-7) x (N) x (2.2) / (1.6)x10^(-3) = 1.7 x 10^(-3) x N = D
Another equation will be from the wire's length.
Total length = Circumference of one loop x No. of turns = πD x N = 2.2
We will eliminate N because we need D.
N = 2.2 / πD
Substitute in 1st equation.
1.7 x 10^(-3) x 2.2 / π = D^2
<span>
D = 0.034 m = 3.4 cm </span>
Answer:
50j
Explanation:
Watts are units used to measure power. power can be defined as rate of energy transfer
500 watts means - 500 J of energy per second
in 1 second - 500 J of work is done
therefore within 10 seconds - 500 J/s x 10 s = 5000 J
work of 5000 J is carried out in 10 seconds
Answer:
E=930.84 N/C
Explanation:
Given that
I = 1150 W/m²
μ = 4Π x 10⁻⁷
C = 2.999 x 10⁸ m/s
E= C B
C=speed of light
B=Magnetic filed ,E=Electric filed
Power P = I A
A=Area=4πr² ,I=Intensity
E=930.84 N/C
Therefore answer is 930.84 N/C