Find three consecutive even integers have a sum of 48.
2 answers:
Answer:
14, 16, 18
Step-by-step explanation:
x + (x+2) + (x+4)= 48
3x + 6 = 48
3x = 42
x = 14
x+2 = 16
x+4 = 18
Answer:
14, 16 and 18
Step-by-step explanation:
let the numbers be defined as x, x+2 and x+4.
Now,
x+x+2+x+4=48
3x+6=48
subtract 6 from both sides
3x=48-6
3x=42
divide both sides by 3
x=42/3=14
therefore
x=14
x+2=16
X+4=18
Hence, the numbers are 14, 16 and 18.
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