Answer:
S
Step-by-step explanation:
Center of the circle: C=(3,8)=(h,k)→h=3, k=8
Radius of the circle: r=5
Standard form of the equation for the circle:
(x-h)^2+(y-k)^2=r^2
(x-3)^2+(y-8)^2=5^2
(x-3)^2+(y-8)^2=25
General for of the equation for the circle:
(x)^2-2(x)(3)+(3)^2+(y)^2-2(y)(8)+(8)^2=25
x^2-6x+9+y^2-16y+64=25
x^2+y^2-6x-16y+73=25
x^2+y^2-6x-16y+73-25=25-25
x^2+y^2-6x-16y+48=0
Answer: The general form of the equation for the circle is:
x^2+y^2-6x-16y+48=0
MAYBE COULD B (8) I guess
Substitute the given into the function
f(-4) = |7(-4) - 3|
now solve
f(-4) = |-28 - 3|
f(-4) = | -31|
the absolute value of |-31| is 31
so,
f(-4) = 31
Hope this helps :)
6 centimeters
x will represent the side length of the smaller square, so 2x is the side length of the bigger square.
x*x + 2x*2x = 45
x^2 + 4x^2 = 45
5x^2 = 45
x^2 = 9 (Divide by 5)
sqrt(x^2) = sqrt(9)
x = 3
2x = 6 (Multiply by 2)
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