Pythagorean Theorema a=24 b=26 c=?

PLZ HELP ME OUT How do I know a number is rational or irrational?

Harrizon [31]

Answer: If a number is rational, it can be represented as a simple fraction, it can be written as a terminating decimal, and a repeating decimal.

If a number is irrational, it cannot be represented as a simple fraction, it cannot be written as a terminating decimal, and not as a repeating decimal. It never ends, never repeats, just like the constant pi.

Step-by-step explanation:

So if a number is rational, it can be represented as a simple fraction, it can be written as a terminating decimal, and a repeating decimal.

If a number is irrational, it cannot be represented as a simple fraction, it cannot be written as a terminating decimal, and not as a repeating decimal. It never ends, never repeats, just like the constant pi.

8 0

2 years ago

Find the height of a square pyramid that has a volume of 8 cubic feet and a base length of 2 feet

Karolina [17]

It would be 6 units high

5 0

2 years ago

Read 2 more answers

Which shows only a vertical translation from the shaded figure onto the unshaded figure?

sergiy2304 [10]

Answer: Its A Im pretty sure

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What’s the answers to these please help!!!

Studentka2010 [4]

Answer:

2): (b) 80

3): (c) 512

4): (c) 4^2+3*(7-2)+4

8 0

2 years ago

A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must h

mestny [16]

Answer:

Radius =6.518 feet

Height = 26.074 feet

Step-by-step explanation:

The Volume of the Solid formed = Volume of the two Hemisphere + Volume of the Cylinder

Volume of a Hemisphere $=\frac{2}{3}\pi r^3$

Volume of a Cylinder $=\pi r^2 h$

Therefore:

The Volume of the Solid formed

$=2(\frac{2}{3}\pi r^3)+\pi r^2 h\\\frac{4}{3}\pi r^3+\pi r^2 h=4640\\\pi r^2(\frac{4r}{3}+ h)=4640\\\frac{4r}{3}+ h =\frac{4640}{\pi r^2} \\h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Area of the Hemisphere = $2\pi r^2$

Curved Surface Area of the Cylinder = $2\pi rh$

Total Surface Area=

$2\pi r^2+2\pi r^2+2\pi rh\\=4\pi r^2+2\pi rh$

Cost of the Hemispherical Ends = 2 X Cost of the surface area of the sides.

Therefore total Cost, C

$=2(4\pi r^2)+2\pi rh\\C=8\pi r^2+2\pi rh$

Recall: $h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Therefore:

$C=8\pi r^2+2\pi r(\frac{4640}{\pi r^2}-\frac{4r}{3})\\C=8\pi r^2+\frac{9280}{r}-\frac{8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{24\pi r^2-8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{16\pi r^2}{3}\\C=\frac{27840+16\pi r^3}{3r}$