There would be 8 tigers in the exhibit. Hope this helps.
Answer:
The Awnser is B
Step-by-step explanation:
Answer:
x^2 y^12
Step-by-step explanation:
( x ^ 1/2 * y ^3 ) ^ 4
A power raised to a power has the exponents multiplied
a^b^c = a^ (b*c)
x^ 1/2 ^ 4 * y^3^4
x^(1/2*4) * y^(3*4)
x^2 y^12
Answer:
B = 0.547
Step-by-step explanation:
edge showed me how
The solution for this problem is:
We know the problem has the following given:
Sample size of 200
X = 182
And the probability of .9005; computation: 1 - .0995 = .9005
So in order to get the probability:
P (x >= 182) = 1 – 0.707134 = .292866 is the probability
that when 200 reservations
are recognized, there are more passengers showing up than there
are seats vacant.
The other solution is:
p (>= 182) = p(183) +
P(184) + P(185) + ... + P(199) + P(200) = 0.292866