Answer
39 bills of 1$
16 bills of 10$
Step-by-step explanation:
x-nr of $1
y-nr of $10
x*1+y*10=199
x+y=55 , x=55-y
so I use the substitution method
(55-y)*1+10y=199
55+10y-y=199
-55 -55
9y=144
y=144/9
y=16
so x=55-16
x=39
verify 16*10+39*1=160+39=199
Answer:
The parcel with weight less than 20.14 pounds are 99% of all parcels under the surcharge weight.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 12 pounds
Standard Deviation, σ = 3.5 pounds
We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.
Formula:
We have to find the value of x such that the probability is 0.99
Calculation the value from standard normal z table, we have,
Thus, parcel with weight less than 20.14 pounds are 99% of all parcels under the surcharge weight.
Judi's share was (7 x $2.50) = $17.50 .
That was really one share out of eight.
So the total bill was
(8 x $17.50) = $140.00 .
When you convert from meters to centimeters, you always multiply by 100, which means that 1 meter = 1 * 100 cm = 100 cm
So, 8.6 meters = 8.6 * 100 cm = 860 cm
Hope this Helps :)
The answer is: " 6.4 blocks " .
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3.2 blocks (one way), PLUS: 3.2 blocks the other way:
3.2 + 3.2 = 6.4 blocks .
or: (3.2) * 2 = 6.4 blocks .
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The answer is: " 6.4 blocks " .
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