If you would like to know what is the cost to insure a car valued at 15400, you can calculate this using the following steps:
$8 ... $1000
$x = ? ... $15400
8 * 15400 = 1000 * x /1000
x = 8 * 15400 / 1000
x = $123.2
The correct result would be $123.2.
<span>I note that this problem starts out with "Which is a factor of ... " This implies that you were given several answer choices. If that's the case, it's unfortunate that you haven't shared them.
I thought I'd try finding roots of this function using synthetic division. See below:
f(x) = 6x^4 – 21x^3 – 4x^2 + 24x – 35
Please use " ^ " to denote exponentiation. Thanks.
Possible zeros of this poly are factors of 35: plus or minus 1, plus or minus 5, plus or minus 7. Use synthetic division; determine whether or not there is a non-zero remainder in each case. If none of these work, form rational divisors from 35 and 6 and try them: 5/6, 7/6, 1/6, etc.
Provided that you have copied down the function
</span>f(x) = 6x^4 – 21x^3 – 4x^2 + 24x – 35 properly, this approach will eventually turn up 1 or 2 zeros of this poly. Obviously it'd be much easier if you'd check out the possible answers given you with this problem.
By graphing this function, I found that the graph crosses the x-axis at 7/2. There is another root.
Using synth. div. to check whether or not 7/2 is a root:
___________________________
7/2 / 6 -21 -4 24 -35
21 0 -14 35
----------- ------------------------------
6 0 -4 10 0
Because the remainder is zero, 7/2 (or 3.5) is a root of the polynomial. Thus, (x-3.5), or (x-7/2), is a factor.
Answer:
just use symbola
and place the two things you have
Step-by-step explanation:
i use it alot it helps you understand the y-intercept and x-intercept and ou can zoom in and zoom out also you can mark the ponts and change the line to make it a different color
Answer:
.026
Step-by-step explanation:
I don't know. But I know how to find it. Let's work it out together:
<u>5x = 2x + 20</u>
Subtract 2x from each side: 3x = 20
Divide each side by 3 : <em>x = 20/3</em> or ( 6 and 2/3 ).
