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Answer with explanation</u>
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Let be the population mean.
As per given , we have
Since the alternative hypothesis is right-tailed , so the test is a right-tailed test.
Also, population standard deviation is given , so we perform one-tailed z-test.
Test statistic :
, where = Population mean
= Population standard deviation
n= sample size
= Sample mean
For n= 18 , , , , we have
P-value (for right tailed test): P(z>2.12) = 1-P(z≤ 2.12) [∵ P(Z>z)=1-P(Z≤z)]\
=1- 0.0340=0.9660
Decision : Since P-value(0.9660) > Significance level (0.01), it means we are failed to reject the null hypothesis.
[We reject null hypothesis if p-value is larger than the significance level . ]
Conclusion : We do not have sufficient evidence to show that the goal is not being met at α = .01 .
Answer:
All real numbers
Step-by-step explanation:
Since 0 does equal 0, and value would be able to work. So any x-value will work. Infinite values for <em>x</em>, resulting in all real numbers.
Answer:
- domain (-∞, ∞)
- range (-∞, 4]
- increasing (-∞, 0)
- decreasing (0, ∞)
- constant (only at x=0, not on any interval)
Step-by-step explanation:
The graph is of the equation y = -x^2 +4. It is a polynomial of even degree, so has a domain of all real numbers: (-∞, ∞).
The vertical extent of the graph includes y=4 and all numbers less than that:
range: (-∞, 4]
The graph is increasing to the left of its vertex at x=0, decreasing to the right.
increasing (-∞, 0); decreasing (0, ∞)
There is no interval on which the function is constant. It has a horizontal tangent at x=0, but a single point does not constitute an interval.
Answer:
l = (S/pi)-r^2
Step-by-step explanation:
Just rearrange the equation.
S = pi*l + pi * r^2
S-pi*r^2 = pi*l
l = (S-pi*r^2)/pi
l = (S/pi)-r^2