All categories

2 years ago

Quicky help????????????

Mathematics

1 answer:

sergeinik [125]2 years ago

5 0

Step-by-step explanation:

first bring 87.5 to right

25t=12.5+87.5

25t=100.0

then bring 25 to right so it will divided

t=100.0/25

t=4

putting value of t in 25t-87.5=12.5

25(4)-87.5=12.5

You might be interested in

A student is saving money to buy a video game. The student currently has $20 and plans to save $10 every month. Write a function

4vir4ik [10]

Answer:

y = amount saved in dollars

x = months

Since the student already has $20 dollars saved (20) and plans to save $10 per month (10x), the equation so far is y = 20 + 10x.

You can use this to solve questions based of the equation/situation by filling in any numbers you are given where the variables are.

Hope this helps! :)

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

The exponential function g, whose graph is given below, can be written as g(x)=a*b^x

sveticcg [70]

Answer:

g(x) = $9(\frac{1}{3})^x$

Step-by-step explanation:

Exponential function 'g' that can be written as g(x) = a.bˣ

From the graph attached,

Graph of the function passes through two points (0, 9) and (1, 3)

g(0) = a.b⁰

9 = a

Similarly, g(1) = a.b¹

3 = a.b

3 = 9(b)

b = $\frac{3}{9}=\frac{1}{3}$

Therefore function will be,

g(x) = $9(\frac{1}{3})^x$

7 0

1 year ago

Maggie’s brother is 12 years younger that three times her age . The sun of their ages is 44 . How old is Maggie

meriva

I'm not sure if this is right but you can set up an equation and solve to find Maggie's age:

Maggie's brother's age = b
Maggie's age = m

b = 12 - 3m
44 = 12-3m
12-3m = 44
-12 -12
-3m = 32
÷ 3 ÷3
m = 10.67

So this would be Maggie's age

I hope this helped :)

7 0

3 years ago

If <img src="https://tex.z-dn.net/?f=%5Crm%20%5C%3A%20x%20%3D%20log_%7Ba%7D%28bc%29" id="TexFormula1" title="\rm \: x = log_{a}(

timama [110]

Use the change-of-basis identity,

$\log_x(y) = \dfrac{\ln(y)}{\ln(x)}$

to write

$xyz = \log_a(bc) \log_b(ac) \log_c(ab) = \dfrac{\ln(bc) \ln(ac) \ln(ab)}{\ln(a) \ln(b) \ln(c)}$

Use the product-to-sum identity,

$\log_x(yz) = \log_x(y) + \log_x(z)$

to write

$xyz = \dfrac{(\ln(b) + \ln(c)) (\ln(a) + \ln(c)) (\ln(a) + \ln(b))}{\ln(a) \ln(b) \ln(c)}$

Redistribute the factors on the left side as

$xyz = \dfrac{\ln(b) + \ln(c)}{\ln(b)} \times \dfrac{\ln(a) + \ln(c)}{\ln(c)} \times \dfrac{\ln(a) + \ln(b)}{\ln(a)}$

and simplify to

$xyz = \left(1 + \dfrac{\ln(c)}{\ln(b)}\right) \left(1 + \dfrac{\ln(a)}{\ln(c)}\right) \left(1 + \dfrac{\ln(b)}{\ln(a)}\right)$

Now expand the right side:

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} \\\\ ~~~~~~~~~~~~+ \dfrac{\ln(c)\ln(a)}{\ln(b)\ln(c)} + \dfrac{\ln(c)\ln(b)}{\ln(b)\ln(a)} + \dfrac{\ln(a)\ln(b)}{\ln(c)\ln(a)} \\\\ ~~~~~~~~~~~~ + \dfrac{\ln(c)\ln(a)\ln(b)}{\ln(b)\ln(c)\ln(a)}$

Simplify and rewrite using the logarithm properties mentioned earlier.

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} + \dfrac{\ln(a)}{\ln(b)} + \dfrac{\ln(c)}{\ln(a)} + \dfrac{\ln(b)}{\ln(c)} + 1$