Find the area of the image below:

Mathematics

1 answer:

s344n2d4d5 [400]2 years ago

8 0

Can you post the image?

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Help plsssssssss ....

Rom4ik [11]

Answer:

Arccos(0.9272) =0.383929333 radian

0.383929333 radian =(0.383929333*57.2957795)degrees

so, 21.99 degrees

Step-by-step explanation:

Rounding to the nearest we get 22 degrees

We know that,

1 radian is equal to 57.2957795

so we multiply the radian value 0.383929333 with it

6 0

2 years ago

Please write the answer

Travka [436]

$\sf \dfrac{3^x - 5 \times 3^{(x-2)}}{3^{(x-3)}} \\ \\ \longrightarrow \sf \dfrac{ {3}^{x} }{ {3}^{(x - 3)}} - \frac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)} \\ \\ \longrightarrow \sf {3}^{[x - (x - 3)]} - \dfrac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ {3}^{(x - 3)} } \times \dfrac{ {3}^{x}}{9} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ \bigg(\dfrac{ {3}^{x} }{ {3}^{3} }\bigg) } \times \dfrac{ {3}^{x}}{9}\\ \\ \longrightarrow \sf {3}^{3} - \dfrac{ ({3}^{3})( 5)}{ {3}^{x} } \times \dfrac{ {3}^{x}}{9}\\ \\ \sf \longrightarrow {3}^{3} - (5 \times 3) \\ \\ \longrightarrow \sf \: 27 - 15 \\ \\ \longrightarrow \leadsto{\underline{\boxed{\sf{ \pink{ 12}}}}}$