N₂ : limiting reactant
H₂ : excess reactant
<h3>Further e
xplanation</h3>
Given
mass of N₂ = 100 g
mass of H₂ = 100 g
Required
Limiting reactant
Excess reactant
Solution
Reaction
<em>N₂+3H₂⇒2NH₃</em>
mol N₂(MW=28 g/mol) :
mol H₂(MW= 2 g/mol) :
A method that can be used to find limiting reactants is to divide the number of moles of known substances by their respective coefficients, and small or exhausted reactans become a limiting reactants
From the equation, mol ratio N₂ : H₂ = 1 : 3, so :
N₂ becomes a limiting reactant (smaller ratio) and H₂ is the excess reactant
Answer:
181.403 g/mol is the answer as it is Zinc chromate
Explanation:
Answer:
Two electrons.
Explanation:
Calcium is the element of second group and forth period. The electronic configuration of Calcium is - 2, 8, 8, 2 or
There are 2 valence electrons of Calcium.
Iodine is the element of seventeenth group and fifth period. The electronic configuration of Iodine is - 2, 8, 18, 18, 7 or
There are 7 valence electrons of iodine.
Calcium iodide, is formed when 2 valence electrons of calcium are loosed and they are gained by 2 atoms of iodine.