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2 years ago

15

Explain what happens to the particles in a substance during a physical change. plllzzzzz hurry!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!

1 answer:

Reptile [31]2 years ago

4 0

Answer:

When a physical change occurs, the arrangement of particles within the substance may change, but the atoms in the molecules remain bonded together.

Explanation:

Srry didn't see this till now, hope u got it right :)

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adoni [48]

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2 years ago

What is the percent composition of H in <br> C<br> 10<br> H<br> 20<br> ?

wolverine [178]

11.19%. This should be right. I have no doubt that you will get it right.

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1 year ago

What best describes the battery in this picture? an electrolytic cell that has spontaneous half reactions

nasty-shy [4]

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2 years ago

Read 2 more answers

2. A block of material has a volume of 2 m3. It has a mass of 1 × 104 kg. Calculate the density of the material sample and expre

maks197457 [2]

Density = mass / volume

D = 1 x 10⁴ / 2

D = 5000 kg/m³ in g/cm³:

1 kg/m³ ---------------- 0.001 g/cm³
5000 kg/m³ ----------- ??

5000 x 0.001 / 1 => 5.0 g/cm³

hope this helps!

7 0

2 years ago

How to set up the rate expressions for the following mechanism?

Anestetic [448]

Answer:

Explanation:

From the given information:

A → B k₁

B → A k₂

B + C → D k₃

The rate law = $\dfrac{d[D]}{dt}=k_3[B][C] --- (1)$

$\dfrac{d[B]}{dt}=k[A] -k_2[B] -k_3[B][C]$

Using steady-state approximation;

$\dfrac{d[B]}{dt}=0$

$k_1[A]-k_2[B]-k_3[B][C] = 0$

$[B] = \dfrac{k_1[A]}{k_2+k_3[C]}$

From equation (1), we have:

$\mathbf{\dfrac{d[D]}{dt}= \dfrac{k_3k_1[A][C]}{k_2+k_3[C]}}$

when the pressure is high;

k₂ << k₃[C]

$\dfrac{d[D]}{dt} = \dfrac{k_3k_1[A][C]}{k_3[C]}= k_1A \ \ \text{first order}$

k₂ >> k₃[C]

$\dfrac{d[D]}{dt} = \dfrac{k_3k_1[A][C]}{k_2}= \dfrac{k_1k_3}{k_2}[A][C] \ \ \text{second order}$

3 0

2 years ago