The equation for a hyperbola is (x-h)/a - (y-k)/b = 1
Or (y-k)/a - (x-h)/b = 1
h represents the x value of the coordinate
k value represents the y value of the coordinate
together they represent a point, which is the center
So (h,k) is (x,y)
The asymptote is y-k = +/- b/a (x-h)
The transverse is the line that goes through the hyperbola.
Answer:
14.4 lb
Step-by-step explanation:
In a see-saw in equilibrium, the torque generated by one side needs to be the same generated in the other side. The torque is calculated by the product between the mass and the distance to the center of the see-saw.
The torque generated by the child is:
T1 = 60 * 3 = 180 lb*feet
So, the torque generated by the weight needs to be higher than T1 in order to lift the child.
The lowest mass is calculated when the mass is in the maximum distance, that is, 12.5 feet from the center.
So, we have that:
T2 = 180 = mass * 12.5
mass = 180/12.5 = 14.4 lb
So the lowest weight is 14.4 lb
A ) The domain:
x ≤ -4 and x≥ 4 or: x ∈ ( - ∞ , - 4 ) ∪ ( 4 , + ∞ )
b ) f ` ( x ) =
c ) The slope of the line normal to the graph at x = 5
m = -1 / f `(x)
f ` ( x ) =
m = - 3/34
Answer:
The expression which represents the quantity of tomatoes and red peppers to buy is $ 2.50 × T + $ 4 × R = $ 20
Step-by-step explanation:
Given as :
The total amount spend for soup = $ 20
The cost of Tomatoes = $ 2.50 per pound
The cost of Red peppers = $ 4 per pound
Let the quantity of tomatoes to be bought = T pound
The quantity of red peppers to be bought = R pound
So, According to question
$ 2.50 × T + $ 4 × R = $ 20
I.e The expression which represents the quantity of tomatoes and red peppers to buy is $ 2.50 × T + $ 4 × R = $ 20 . Answer
I believe your answer is going to be C.