To solve this, first we'll find the area of the rectangle A,
Area=length × width
?=24m×20m
480m=24m×20m
480m squared=area of the rectangle A
now we'll find the width of rectangle B,
"the width of rectangle B is 12 meters less than the width of rectangle A",
20m-12m= 8m
8m=width of rectangle B
finally we'll find the length of rectangle B,
area of the rectangle B= 480msquared
width= 8m
length=? (to find this divide the area by the width)
480÷8=60m
length of the rectangle B=60m
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We check with each options
'Or' represents the intersection of two graphs
'And' represents two separate graphs'
We have two separate shaded part in the given graph
So we ignore the options that has 'and' in between
LEts check first and second option
Simplify the first part and second part
multiply both sides by 2 .
x < 2 or 4x - 2 > = 26
solve 4x-2 > = 26
add 2 on both sides and then divide both sides by 4
4x >= 28
x >= 7
So solution is x<2 or x>=7 . that is the graph on number line
Lets check with second option
3x-3<3 or 2x+8>=22
add 3 on both sides
3x < 6
divide both sides by 3
so x< 2
2x+8>=22
subtract 8 on both sides
2x >= 30
divide both sides by 2
x >= 15
x<2 or x>=15 that does not satisfies the graph
So option A is correct
Answer:
A
Step-by-step explanation:
- 1/5 of 5x is -1 or just -x and -1/5 of 20 is -4. Then the other one is-1/4 of 4 is -x and -1/4 of -28 is 7. Now combine like terms so -x + -x is -2x and 7+ -4 or 7-4 is 3
Answer:
angle B: 39
AC: 7.288
AB: 11.58
(note: you cut off the part about rounding so make sure that it's rounded correctly before you put in your answer)
Step-by-step explanation:
To solve this we will use SOH, CAH, TOA
we have the angle and the one opposite to it which means we can use either SOH or TOA
let's use TOA
tan(51)=(9/x)
x= 7.288
We can now use pahtagaryous theroem to solve for the hyptonouse
we have
9²+7.288²=C²
C=11.58
Finally, to find angle B we will recall that the angles of a triangle must add to 180.
51+90+a=180
a=39