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2 years ago

2. A rectangle has a width, w and a length that is 3 more than 2 times longer than the width.

Mathematics

1 answer:

nika2105 [10]2 years ago

7 0

Answer:

2w+2(3+2w)=P, w*(3+2w)=A

Step-by-step explanation:

if w is 2, then P=4+14, and A=2*7.

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The measure of a vertex angle of an isosceles triangle is 120° and the length of a leg is 8 cm. Find the length of a diameter of

Goryan [66]

ANSWER

The length of a Diameter is 3.714

EXPLANATION

The circumscribed triangle is shown in the attachment.

We use the cosine ratio to find the altitude of the isosceles triangle.

$\cos(60 \degree) = \frac{altitude}{hypotenuse}$

$\cos(60 \degree) = \frac{altitude}{8}$

Altitude =8cos(60°)

Altitude=4cm

Let the upper half of the altitude be y cm.

Then the radius of the circle is (y-4)cm

The upper radius meets the tangent at right angles.

From the smaller right triangle,

$\sin(60 \degree) = \frac{4 - y}{y}$

$y\sin(60 \degree) = 4 - y$

$y\sin(60 \degree) + y= 4$

$(\sin(60 \degree) + 1)y= 4$

$y= \frac{4}{\sin(60 \degree) + 1}$

$y = 16 - 8 \sqrt{3}$

y=1.857

The diameter is 2y

$d = 32 - 16 \sqrt{3}$

=2(1.875)

The length of a Diameter is 3.714

7 0

2 years ago

Read 2 more answers

You plan to build a house that is 1 ½ times as long as it is wide. You want the land around the house to be 20 feet wider than t

IgorLugansk [536]

The total area with land based on the information given is 3x² + 60x.

Let the width = x

Let the length = (1.5 × x) = 1.5x

Area = 1.5x × x = 1.5x²

The area along with land:

Width = x + 20

Length = 3 × x = 3x

The total area with land:

= Length × Width

= 3x(x + 20)

= 3x² + 60x.

Learn more about length on:

brainly.com/question/2217700

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7 0

1 year ago

-3q + 12 greater than equal too 4q - 30 solve for q

valentina_108 [34]

Solving the inequality $-3q+12\geq 4q-30$ the value of q is $q\leq 6$

Step-by-step explanation:

We need to solve the inequality: $-3q+12\geq 4q-30$ and find value of q

Solving:

$-3q+12\geq 4q-30\\Adding\,\,-12\,\,on\,\,both\,\,sides:\\-3q+12-12\geq 4q-30-12\\-3q\geq 4q-42\\Adding\,\,-4q\,\,on\,\,both\,\,sides:\\-3q-4q\geq 4q-42-4q\\-7q\geq -42\\Divide\,\,both\,\,sides\,\,by\,\,7\\\frac{-7q}{7}\geq \frac{-42}{7}\\ -q\geq -6\\Multiply\,\,both\,\,sides\,\,by\,\,-1\,\,and\,\,reverse\,\,the\,\,inequality:\\q\leq 6$