To find slope given two points, there is a formula you can use: (y2-y1)/(x2-x1). Y2 stands for the second y coordinate and y1 stands for the first y coordinate. The same logic applies to the x's. Let's assume that (3, -2) is x1, y1 and (4,7) is x2, y2. Let's plug them into the formula.
(7-(-2))/(4-3).
7-(-2)=9 for total y value.
4-3=1 for the x value.
Now we divide them.
9/1=9. 9=m. M is the variable commonly used for slope. Hope this helped!
The
4th selection is appropriate:
The first line is a dashed line which joins ordered pairs (-2, 1) and (3, 1). The second line is a dashed line and joins ordered pairs (-2, -2) and (3, 3). The portion common above the first line and above the second line is shaded
18. If f(x)=[xsin πx] {where [x] denotes greatest integer function}, then f(x) is:
since x denotes the greatest integers which could the negative or the positive values, also x has a domain of all real numbers, and has no discontinuous point, then x is continuous in (-1,0).
Answer: B]
20. Given that g(x)=1/(x^2+x-1) and f(x)=1/(x-3), then to evaluate the discontinuous point in g(f(x)) we consider the denominator of g(x) and f(x). g(x) has no discontinuous point while f(x) is continuous at all points but x=3. Hence we shall say that g(f(x)) will also be discontinuous at x=3. Hence the answer is:
C] 3
21. Given that f(x)=[tan² x] where [.] is greatest integer function, from this we can see that tan x is continuous at all points apart from the point 180x+90, where x=0,1,2,3....
This implies that since some points are not continuous, then the limit does not exist.
Answer is:
A]