Step-by-step explanation:
A study was to be undertaken to determine if a particular training program would improve physical fitness. A sample of 31 university students was selected to be enrolled in the fitness program. The researchers wished to determine if there was evidence that their sample of students differed from the general population of untrained subjects. The sample mean is 47.4 and a standard deviation of 5.3. The 98% confidence interval is determined and is given as, (45.2, 49.6) .
If the level of confidence is changed to 95%, then the confidence interval will become shorter but the p-value will not change because it is calculated using the test statistic. So the correct answer is (a).
Percents to a decimal is easier to understand just take the percent so say it is 35% the decimal form would be .35 or 5% .05, and for the percent to a fraction just take the percent such as 30/100 and make sure it is in the simplest form to solve so that would be 3/10.
Answer:
n=36
Step-by-step explanation:
I dont know if thats how it was set up but here you go. I hope this helps. (I can change it if thats not how its set up)