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3 years ago

Classify each number as rational or irrational.

1 answer:

4 0

Not sure if this is totally 100% correct, but I have this on my test and I just got -- 11/3 - irrational
√48 - irrational
6.25 (= 6 1/4) - rational
0.01045 - irrational
√16/81 - irrational
√3/16 - rational
0.42(repeating) - irrational
16(pi) - irrational

Hope I helped?

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There are over 2700 species of snakes in the world over 600 are venomous Express the fraction of species that are not venomous a

Andre45 [30]

You do 600 divided by 2700 and you end up with 22/100 or 0.22 as a decimal. So if 0.22 or 22/100 are venimous then 78/100 or 0.78 are non venimous. I understand its a bit confusing and i can simplify it for you but still I hope this helps :)

6 0

2 years ago

Write each fraction as the sum of a whole number and a fraction less than 1

Tpy6a [65]

Given:

The fractions are:

$\dfrac{6}{5},\dfrac{11}{7},\dfrac{21}{4}$

To find:

The each fraction as the sum of a whole number and a fraction less than 1.

Solution:

The given fraction is $\dfrac{6}{5}$ .

$\dfrac{6}{5}=\dfrac{5+1}{5}$

$\dfrac{6}{5}=\dfrac{5}{5}+\dfrac{1}{5}$

$\dfrac{6}{5}=1+\dfrac{1}{5}$

Therefore, the given fraction $\dfrac{6}{5}$ can be written as $1+\dfrac{1}{5}$ .

The given fraction is $\dfrac{11}{7}$ .

$\dfrac{11}{7}=\dfrac{7+4}{7}$

$\dfrac{11}{7}=\dfrac{7}{7}+\dfrac{4}{7}$

$\dfrac{11}{7}=1+\dfrac{4}{7}$

Therefore, the given fraction $\dfrac{11}{7}$ can be written as $1+\dfrac{4}{7}$ .

The given fraction is $\dfrac{21}{4}$ .

$\dfrac{21}{4}=\dfrac{20+1}{4}$

$\dfrac{21}{4}=\dfrac{20}{4}+\dfrac{1}{4}$

$\dfrac{21}{4}=5+\dfrac{1}{4}$

Therefore, the given fraction $\dfrac{21}{4}$ can be written as $5+\dfrac{1}{4}$ .

7 0

2 years ago

The answer is red show step by step of the pro tem to get the answer

miskamm [114]

In order to rationalize the denominator of each expression, we need to multiply the expression by the same radical in the denominator, this way we can remove the radical from the denominator.

$\frac{5\sqrt{4}}{\sqrt{3}}(\cdot\sqrt{3})=\frac{5\sqrt{4}\sqrt{3}}{(\sqrt{3})^2}=\frac{5\cdot2\cdot\sqrt{3}}{3}=\frac{10\sqrt{3}}{3}$

10)

$-\frac{5}{3\sqrt{2}}(\cdot\sqrt{2})=-\frac{5\sqrt{2}}{3(\sqrt{2})^2}=-\frac{5\sqrt{2}}{3\cdot2}=-\frac{5\sqrt{2}}{6}$

11)

$\frac{2\sqrt{3}}{4\sqrt{5}}(\cdot\sqrt{5})=\frac{2\sqrt{3}\sqrt{5}}{4(\sqrt{5})^2}=\frac{2\sqrt{15}}{4\cdot5}=\frac{\sqrt{15}}{2\cdot5}=\frac{\sqrt{15}}{10}$

12)