Im factoring and i need to find what times what equals 120 but subtracts to be 7

1.)Given the recursive definition LaTeX: a_{n+1}=2\cdot a_n+1a n + 1 = 2 ⋅ a n + 1, and that LaTeX: a_1=1a 1 = 1, find LaTeX: a_

aksik [14]

Answer:

1) 1023

2) 8

Step-by-step explanation:

1)

Given:

$a_{n+1}=2\cdot a_n + 1$ and $a_1 = 1$

Then, the next table can be computed (only the first terms are explicitely shown)

n $a_n$

1 1

2 $a_{2}=2\cdot 1 + 1 =$ 3

3 $a_{3}=2\cdot 3 + 1 =$ 7

4 15

5 31

6 63

7 127

8 255

9 511

10 1023

2)

Given

$t_n=n^2-2n$

Then, the next table can be computed

n $t_n$

1 $t_1=1^2-2(1) =$ -1

2 $t_2=2^2-2(2) =$ 0

3 $t_3=3^2-2(3) =$ 3

4 $t_4=4^2-2(4) =$ 8

4 0

2 years ago

= The average score of Karl's first four math tests is 72 points. After the fifth and the sixth tests, his average score increas

mylen [45]

Answer:

83 points

Step-by-step explanation:

-The formula for average is given as:

$\bar X=\frac{1}{n}\sum{x_i}\\\\x_i=Individual \ Test \ scores\\n=number \ of \ scores$

Let a be his 5th score and (a+4) of the 6th

#We subtract the sum of the first 4 tests from the 6, to get the sum of the 5th and 6th tests:

$(6^{th}+5^{th})=\bar X n_6-\bar X n_4\\\\=75\times 6-72\times 4\\\\=162$

#We substitute for the 5th and 6th to solve a:

$5^{th}=a\\6^{th}=a+4\\\\a+(a+4)=162\\\\2a=158\\\\a=79\\\\6^{th}=a+4=79+4=83$

Hence, Karl score 83 points in his 6th test.

5 0

2 years ago

Can anyone help with 20-22?

aliina [53]

Answer:

zx would equal 19 as well

wt=4.5

wy=19

Step-by-step explanation:

this is easy speacily since i am in 8th grade lol

3 0

2 years ago

Please helppppppppppppp

Elenna [48]

Answer:

f(-7) = 2

Step-by-step explanation:

f(x) = x + 9

We want to find f(-7)

f(-7) = -7 + 9

-7 + 9 is the same thing as saying 9 - 7

9 - 7 = 2

So f(-7) = 2

3 0

1 year ago

Find the value of y and z

elena55 [62]

$\qquad\qquad\huge\underline{{\sf Answer}} \huge♨$

In the given figure, NQ acts as a diameter and since diameter subtends 90° at the arc of the circle, so we can conclude that ~

$\qquad \sf \dashrightarrow \:3y = 90 \degree$

$\qquad \sf \dashrightarrow \:y = 90 \degree \div 3$

$\qquad \sf \dashrightarrow \:y = 30 \degree$

Now, Let's use Angle sum property of Triangle to solve for z :

$\qquad \sf \dashrightarrow \:4z + 3y + 50 \degree = 180 \degree$

$\qquad \sf \dashrightarrow \:4z +90 \degree + 50 \degree = 180 \degree$

$\qquad \sf \dashrightarrow \:4z = 180 \degree - (50 \degree + 90\degree)$

$\qquad \sf \dashrightarrow \:4z = 180 \degree - (140\degree)$

$\qquad \sf \dashrightarrow \:4z = 40 \degree$

$\qquad \sf \dashrightarrow \:z = 40 \degree \div 4$

$\qquad \sf \dashrightarrow \:z = 10 \degree$

I hope you understood the procedure, you can ask me in comments if you have any doubts.

3 0

1 year ago