Answer:
Bb and Bb
Explanation:
Let B be the allele of a black color; &
Let b be the allele of a white color
Allele B is dominant over allele b, and as such it masks the expression of allele b
If we have a cross between two heterozygous individuals
i.e Bb × Bb
we have:
B b
B BB Bb
b Bb bb
From above, Phenotypically;
we have the following offspring:
BB ; one normal black color
2 Bb: two heterozygous for black color
bb : one white color
The color ratio is in the ratio of 3 black :1 white which is synonymous to 10 black : 3 white
So; we can therefore conclude that the genotype of the parents are :
Bb and Bb